What is the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1)?

A circle with center (h, k) has equation (x − h)² + (y − k)² = r². The distance from (−4, 0) to (−2, 1) has square (−2 + 4)² + (1 − 0)² = 2² + 1² = 5, so the equation is (x + 4)² + y² = 5, choice C.

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