Two vectors with magnitudes of 6 and 9 have a dot product equal to –27.Find the angle between the vectors.

Use the dot product formula: a · b = |a||b| cos θ. Substituting the values gives −27 = 6 × 9 × cos θ, so cos θ = −27/54 = −1/2. The angle with cosine −1/2 is 120°, so the answer is B, 120°.

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