Limits and Continuity Answers

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Which statement describes the piecewise function when x = –6?

Question illustration
A
Since = 36 and f(x) = 36, the function is continuous when x = –6.
Option A
B
Since ⁡f(x) = –36 and f(x) = –36, the function is continuous when x = –6.
Option B
C
Since f(x) = –36 and f(x) = 36, the function is not continuous when x = –6.
Option C
D
Since ⁡ f(x) = 36 and f(x) = –36, the function is not continuous when x = –6.
Option D
6

For which functions can the extreme value theorem be applied? Check all that apply. over the interval [–2, 0] over the interval [4, 10]f(x) = x2 + 1 over the interval (0, 2)f(x) = (x – 2)3 over the interval (–10, –4] over the interval [–3, 3]

Question illustration
A
over the interval [–2, 0]
Option A
B
over the interval [4, 10]
Option B
C
f(x) = x2 + 1 over the interval (0, 2)
D
f(x) = (x – 2)3 over the interval (–10, –4]
E
over the interval [–3, 3]
Option E
11

The type of discontinuity is .

A
jump
B
mixed
C
infinite
D
endpoint

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