The distributive property can be applied to which expression to factor 12x3 – 9x2 + 4x – 3?

Factor by grouping: 12x³ − 9x² + 4x − 3 = (12x³ − 9x²) + (4x − 3). Factoring each group gives 3x²(4x − 3) + 1(4x − 3), which matches choice D. Both terms share the factor (4x − 3), so the expression can then be written as (4x − 3)(3x² + 1).

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