Question 6 • OK-Algebra II A
First multiply the monomials: (a²)(2a³) = 2a⁵. Distribute 2a⁵ across each term in the parentheses: 2a⁵·a² = 2a⁷, 2a⁵·(−8a) = −16a⁶, and 2a⁵·9 = 18a⁵. The product is 2a⁷ − 16a⁶ + 18a⁵, which is choice A.
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