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Question 6 • *25-26 KCS18 Chemistry IC

Complete this example: A 0.67 molal solution was made by dissolving glucose in water. The boiling point of pure water is 100.00°C. The boiling point constant for water is 0.51°C·kg/mol.Set up the problem. T = (0.51C•kg/mole)(0.67 m) What is the T value? C

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Answer
A
0.34
B
0.39
C
0.51
D
0.68
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