The solutions to 15(2a – 2) = 5(a2 – 1) are:

Expand both sides: 15(2a − 2) = 30a − 30 and 5(a² − 1) = 5a² − 5. Rearranging gives 5a² − 30a + 25 = 0, or a² − 6a + 5 = 0. Factoring gives (a − 1)(a − 5) = 0, so a = 1 or a = 5. The correct choice is C, a = 5 and a = 1.

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