Question 3 • FL-1200330-Algebra 2 CR
The logarithms require x > 0. Combine the terms to get log₃(2x⁴ + 8x³) = 5log₃x, so 2x⁴ + 8x³ = x⁵. Factoring out x³ and using x > 0 gives x² − 2x − 8 = 0, with potential solutions x = 4 and x = −2. Since −2 is outside the logarithm’s domain, only x = −2 is extraneous.
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