If Beaker #2 is a 1% solution of Y, and Beaker #3 is 1/100th of that in the final solution, what percentage solution would Beaker #3 be?

Beaker #3 contains 1/100 of Beaker #2’s 1% concentration. Calculate 1% ÷ 100 = 0.01%. Therefore, Beaker #3 is a 0.01% solution, choice C.

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