Use a graphing calculator and the parametric equations y = 6sin(t2) and x = 8cos(t2) determine the location of the graph when –1.5 ≤ t ≤ 1.5.

As t ranges from −1.5 to 1.5, t² ranges from 0 to 2.25. Thus y = 6sin(t²) is positive for t² between 0 and 2.25, while x = 8cos(t²) is positive up to t² = π/2 and negative after that. The graph therefore lies in Quadrants I and II (also touching the positive x-axis at t = 0), so the correct choice is “Quadrants I and II.”

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