Question 3 • FL-1200310-Algebra 1 A
Distribute each term in 2p + q across –3q – 6p + 1: (2p)(–6p) = –12p², and the two pq products are –6pq and –6pq, totaling –12pq. The remaining products are –3q², +2p, and +q, so the result is –12p² – 12pq + 2p – 3q² + q, which matches choice B.
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