6
AssignmentDropdown

Relations and Functions

Question 6 • FL-1200330-Algebra 2 Sem 1 - Flex

r(x) = –x² + 3x s(x) = 2x + 1(s – r)(x) =

Answer
A
–x² + 3x – 2x + 1
B
(–x² + 3x) – (2x + 1)
C
(2x + 1) – (–x² + 3x)
D
2x + 1 – x² + 3x

Explanation

To find (s − r)(x), subtract r(x) from s(x): (2x + 1) − (−x² + 3x). This matches choice C. Distributing the subtraction gives x² − x + 1.

AI-written and checked against the verified answer.

Previous
Next