Question 5 • FL-1200330-Algebra 2 Sem 1 - Flex
The interval −8 < x < 2 contains values such as −2. Substituting −2 into the original inequality gives |−2 + 3| < 5, or 1 < 5, which is true, so A verifies the solution set. The value 6 is outside the interval, and |6 + 3| < 5 becomes 9 < 5, which is false, so D also verifies it.
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