5
AssignmentMultiple Select

Inequalities

Question 5 • FL-1200330-Algebra 2 Sem 1 - Flex

Which statements verify that the solution set to |x + 3| < 5 is –8 < x < 2? Check all that apply.

Answer
A
Substituting a value into the inequality from the solution set, such as –2, will create a true statement.
B
Substituting a value into the inequality from the solution set, such as 1, will create a false statement.
C
Substituting a value into the inequality not from the solution set, such as 4, will create a true statement.
D
Substituting a value into the inequality not from the solution set, such as 6, will create a false statement.
E
Substituting any value into the inequality will create a true statement.

Explanation

The interval −8 < x < 2 contains values such as −2. Substituting −2 into the original inequality gives |−2 + 3| < 5, or 1 < 5, which is true, so A verifies the solution set. The value 6 is outside the interval, and |6 + 3| < 5 becomes 9 < 5, which is false, so D also verifies it.

AI-written and checked against the verified answer.