AnswersWI-Geometry BUnit Test

Introduction to Circles Answers

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Use the diagram to complete the statement.

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A
cos(38°).
B
cos(52°).
C
tan(38°).
D
tan(52°).
4
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Triangle ABC is a sketch of a triangular flower bed that has an area of 65.1 square feet.Trigonometric area formula: Area =

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A
17 feet
B
33 feet
C
40 feet
D
50 feet
5

Triangle ABC is a right triangle and cos(22.6o)=. Solve for b and round to the nearest whole number.

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A
tan(22.6o) =
Option A
B
tan(22.6o) =
Option B
C
tan(22.6o) =
Option C
D
tan(22.6o) =
Option D
6

The law of cosines for RST can be set up as 52 = 72 + 32 – 2(7)(3)cos(S). What could be true about RST?Law of cosines: a2 = b2 + c2 – 2bccos(A)

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A
r = 5 and t = 7
B
r = 3 and t = 3
C
s = 7 and t = 5
D
s = 5 and t = 3
7

A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm.What is the approximate area of the triangle? Round to the nearest tenth.Area of a triangle = bh

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A
68.7 cm2
B
161.8 cm2
C
381.3 cm2
D
450.0 cm2
8

Law of sines:

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A
15°
B
30°
C
45°
D
60°
9

Which measures are accurate regarding triangle JKL? Select two options.

A
m∠K = 94°
B
k ≈ 3.7 units
C
k ≈ 4.6 units
D
KL ≈ 2.5 units
E
KL ≈ 3.2 units
10

Heron’s formula: Area =

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A
27 square units
B
38 square units
C
364 square units
D
728 square units
11

In which triangle is the value of x equal to tan−1? (Images may not be drawn to scale.)

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A
A right triangle is shown. The length of the hypotenuse is 5.2 and the length of the side adjacent to the right angle is 3.1. The angle between the 2 sides is x.
Option A
B
A right triangle is shown. The length of the hypotenuse is 5.2 and the length of the side adjacent to the right angle is 3.1. The angle opposite to side with length 3.1 is x.
Option B
C
A right triangle is shown. The length of 2 sides are 5.2 and 3.1. The angle opposite to side with length 5.2 is x.
Option C
D
A right triangle is shown. The length of 2 sides are 5.2 and 3.1. The angle opposite to side with length 3.1 is x.
Option D
12

Triangle L J K is shown. Angle J L K is a right angle. The length of the hypotenuse is 15 inches and the length of the side adjacent to the right angle is 10 inches. The angle between the 2 sides is x.

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A
sin(x) =
Option A
B
sin(x) =
Option B
C
cos(x) =
Option C
D
cos(x) =
Option D
13

The equation can be used to find the length of .

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A
19.3 in.
B
21.3 in.
C
23.5 in.
D
68.0 in.
14

Which equation can be used to find the length of ?

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A
(10)sin(40o) = AC
B
(10)cos(40o) = AC
C
= AC
Option C
D
= AC
Option D
15

In right triangle XYZ, the right angle is located at vertex Y. The length of line segment XY is 12.4 cm. The length of line segment YZ is 15.1 cm.

A
34.8°
B
39.4°
C
50.6°
D
55.2°
16

Law of cosines: a2 = b2 + c2 – 2bccos(A)

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A
35°
B
45°
C
55°
D
65°
17

Two teams are pulling a heavy chest, located at point X. The teams are 4.6 meters away from each other. Team A is 2.4 meters away from the chest, and Team B is 3.2 meters away. Their ropes are attached at an angle of 110°.Law of sines:

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A
StartFraction sine (uppercase A) Over 2.4 EndFraction = StartFraction sine (110 degrees) Over 4.6 EndFraction
Option A
B
StartFraction sine (uppercase A) Over 4.6 EndFraction = StartFraction sine (110 degrees) Over 2.4 EndFraction
Option B
C
StartFraction sine (uppercase A) Over 3.2 EndFraction = StartFraction sine (110 degrees) Over 4.6 EndFraction
Option C
D
StartFraction sine (uppercase A) Over 4.6 EndFraction = StartFraction sine (110 degrees) Over 3.2 EndFraction
Option D
18

Law of sines:

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A
only 90°
B
only 155°
C
20° and 110°
D
45° and 135°
19

Law of cosines: a2 = b2 + c2 – 2bccos(A)

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A
34°
B
41°
C
51°
D
56°
20

The equation can be used to find the measure of angle LKJ.

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A
41°
B
45°
C
49°
D
55°
21

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the length of B C is 24.

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A
Five-thirteenths
Option A
B
Twelve-thirteenths
Option B
C
Twelve-fifths
Option C
D
Thirteen-twelfths
Option D
22

A kite is made up of two isosceles triangles, KIT and KET, with the lengths shown. The top triangle of the kite, ΔKIT, is made from approximately 17 square inches of material.Heron’s formula: Area =

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A
31 square inches
B
34 square inches
C
48 square inches
D
62 square inches

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