AnswersHVA 26-27 IM Biology ALab: Diffusion Across a Semi-permeable Membrane

Lab: Diffusion Across a Semi-permeable Membrane Answers

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the dialysis tubing. After 15 minutes, a sample was taken. That sample showed that glucose was found:inside
the dialysis tubing.:outside
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was molecule shapeability to diffuserate of diffusion.

A
molecule shape
B
ability to diffuse
C
rate of diffusion
3

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. The beaker:starch solution and Lugol’s solution
.:only Lugol’s solution
4

contains only Lugol’s solution starch solution and Lugol’s solution.

A
only Lugol’s solution
B
starch solution and Lugol’s solution
8

If a test had been done of the solution inside the dialysis tube, what do you think the results would have been?

A
No glucose would be found because it all moved outside the tubing.
B
No glucose would be found because glucose was not placed inside the dialysis tube.
C
The glucose would be found because it would reach an equilibrium.
9

Analysis: Both glucose and starchNeither glucose nor starchOnly starch (larger molecules) ✔ Only glucose (smaller molecules) diffused though the semipermeable membrane.

A
Both glucose and starch
B
Neither glucose nor starch
C
Only starch (larger molecules)
D
✔ Only glucose (smaller molecules)
10

Starch molecules are too large to pass through the tubing into the beaker. Which errors could have caused starch to appear in the beaker despite this fact? Check all possible errors.

A
not washing the outside of the tubing after filling it with starch
B
reusing droppers for different solutions
C
adding glucose to the solution in the dialysis tubing
D
using a beaker that had not been cleaned thoroughly
11

Based on what you learned in the lab, why does your body need to break down starch into glucose?

A
Starch contains more energy than glucose.
B
Starch molecules are too large to diffuse into cells.
C
Glucose molecules are larger than starch molecules.
12

contains starch solution Lugol’s solution starch solution and Lugol’s solution.

A
starch solution
B
Lugol’s solution
C
starch solution and Lugol’s solution
13

insideoutsideX both inside and outsideneither inside nor outside the dialysis tubing.

A
inside
B
outside
C
both inside and outside
D
neither inside nor outside
15

The tubing contains starch solution Lugol’s solution starch solution and Lugol’s solution. The beaker

A
starch solution
B
Lugol’s solution
C
starch solution and Lugol’s solution
16

contains ✔ only Lugol’s solution starch solution and Lugol’s solution.

A
✔ only Lugol’s solution
B
starch solution and Lugol’s solution
17

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Answers:
.:only Lugol’s solution
19

If a test had been done of the solution inside the dialysis tube, what do you think the results would have been?

A
No glucose would be found because it all moved outside the tubing.
B
No glucose would be found because glucose was not placed inside the dialysis tube.
C
The glucose would be found because it would reach an equilibrium.
20

Analysis: Both glucose and starchNeither glucose nor starchOnly starch (larger molecules) ✔ Only glucose (smaller molecules) diffused though the semipermeable membrane.

A
Both glucose and starch
B
Neither glucose nor starch
C
Only starch (larger molecules)
D
✔ Only glucose (smaller molecules)

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