AnswersAA-F26 Physical ScienceNewton's Laws of Motion

Lab: Newton's Laws of Motion Answers

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mass of the car✔ car hitting a barriernumber of washers

A
mass of the car
B
✔ car hitting a barrier
C
number of washers
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✔ velocity of the washermass of the washermass of the car

A
✔ velocity of the washer
B
mass of the washer
C
mass of the car
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mass of the car✔ force applied to the carangle of the track

A
mass of the car
B
✔ force applied to the car
C
angle of the track
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✔ acceleration of the carnumber of washersmass of the car

A
✔ acceleration of the car
B
number of washers
C
mass of the car
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kilograms✔ meters per secondmeters per second squarednewtons

A
kilograms
B
✔ meters per second
C
meters per second squared
D
newtons
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kilogramsmeters per second✔ meters per second squarednewtons

A
kilograms
B
meters per second
C
✔ meters per second squared
D
newtons
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kilogramsmeters per secondmeters per second squared✔ newtons

A
kilograms
B
meters per second
C
meters per second squared
D
✔ newtons
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✔ kilogramsmeters per secondmeters per second squarednewtons

A
✔ kilograms
B
meters per second
C
meters per second squared
D
newtons
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⇒ 0.11

Answers:
Blank 1:0.11
Blank 2:0.28
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⇒ 0.28

Answer:

0.28

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A✔ BC

A
A
B
✔ B
C
C
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✔ ABC

A
✔ A
B
B
C
C
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AB✔ C

A
A
B
B
C
✔ C
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Use what you know about mass and how you use it to calculate force in the following situation.

Answers:
If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be .:0.0098 kg
Given that F = ma, and if 4 washers are attached to the string and car instead of 2, then the applied force on the car will be . Recall a = 10 m/s2:0.196 N
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98 N✔ 0.196 N0.0049 N

A
98 N
B
✔ 0.196 N
C
0.0049 N

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