In triangle ABC shown, sine cap c is equal to h over A and sine cap A is equal to h over c Which of the following combines the two sine ratios into one equation?

From sin C = h/A, multiply both sides by A to get A sin C = h. From sin A = h/c, multiply both sides by c to get c sin A = h. Since both expressions equal h, A sin C = c sin A, which is choice C.

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