Law of Sines and Law of Cosines — a Deeper Look Answers

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✔ b2 - 2bx + x2b2 + x2

A
✔ b2 - 2bx + x2
B
b2 + x2
3

+2bx✔ -2bx

A
+2bx
B
✔ -2bx
4

4) c2 = h2 + b2 -2bx + x2Pythagorean theoremRearrange the previous statementAssumption✔ Expand (b – x)2

A
Pythagorean theorem
B
Rearrange the previous statement
C
Assumption
D
✔ Expand (b – x)2
5

Question text not available

Answers:
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:a2 - x2
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:b2 - 2bx + x2
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:-2bx
6

x2 - a2✔ a2 - x2

Answers:
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:a2 - x2
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:b2 - 2bx + x2
1) a2 = h2 + x2 2) h2 = 3) c2 = h2 + (b − x)2 4) c2 = h2 + 5) c2 = a2 − x2 + b2 − 2bx + x2 6) c2 = a2 + b2 7) x = acosC 8) c2 = a2 + b22abcosC:-2bx
8

Which of the following statements are true? Check all of the boxes that apply.

A
Triangle ABC is a right triangle.
B
Segment h divides triangle ABC into two congruent triangles
C
Segment h divides triangle ABC into two right triangles.
D
a2 = b2 + c2
E
c2 = h2 + b2 - 2bx + x2
F
If you know sides a, b, and c, you can find all the angles of triangle ABC.
13

2) h2 = a2 - x2Pythagorean theorem✔ Rearrange the previous statementAssumptionExpand (b – x)2

A
Pythagorean theorem
B
✔ Rearrange the previous statement
C
Assumption
D
Expand (b – x)2
15

3) c2 = h2 + (b-x)2✔ Pythagorean theoremRearrange the previous statementAssumptionExpand (b – x)2

A
✔ Pythagorean theorem
B
Rearrange the previous statement
C
Assumption
D
Expand (b – x)2

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