In the triangle shown on the right, ÐP = 55°, n = 10, and g = 12. Find the remaining side and the two angles. Round all answers to the nearest tenth.Length of side p =

The sides n = 10 and g = 12 meet at angle P = 55°, so use the Law of Cosines: p² = 10² + 12² − 2(10)(12)cos(55°), giving p ≈ 10.3. Then the Law of Sines gives angle N ≈ 52.6°. Since the angles of a triangle total 180°, angle G ≈ 180° − 55° − 52.6° = 72.4°. The remaining side is 10.3, choice A.

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