Lesson 1.1: Solving Equations Answers

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What is the value of x in the equation 6(x + 1) – 5x = 8 + 2(x – 1)?

A
0
B
StartFraction 5 Over 4 EndFraction
Option B
C
StartFraction 7 Over 4 EndFraction
Option C
D
12
3

The sum of three numbers is 45. The second of the three numbers is three more than twice the first number, x. The third number is two more than the first number, x. Which equation can be used to solve for the first number, x?

A
x + 5x + x + 2 = 45
B
x + x + 3 + x + 2 = 45
C
x + 3x + 2 + x + 2 = 45
D
x + 2x + 3 + x + 2 = 45
4

Five times a number decreased by nine is equal to twice the number increased by 23. Which equation could be used to solve the problem?

A
5x – 9 = x + 23
B
5x – 9 = 2x + 23
C
5x + 23 + 2x = 23
D
5x + 23 = 2x + 23
5

What is the value of x in the equation 2x – 3 = 9 – 4x?

A
–6
B
–3
C
1
D
2
6

Three times a number, x, increased by four is equal to five times the number, x. Which equation can be used to solve for x?

A
3 x + 5 x = 4
Option A
B
3 x + 4 = 5 x
Option B
C
3 x = 4 + 5 x
Option C
D
3 x minus 4 = 5 x
Option D
7

What is the solution to the equation ?

Question illustration
A
x = 12
B
x = 14
C
x = 16
D
x = 26
8

Rachna has nickels, dimes, and quarters in her piggy bank. She has $4.65 altogether. She has three more quarters than dimes and twice as many nickels as quarters. How many quarters does Rachna have?

A
8
B
11
C
22
D
41
9

The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?

A
x + x + x = 131
B
x + (x + 7) + (x – 12) = 131
C
x + (2x + 7) + (x – 12) = 131
D
x + (2x + 7) – 12 = 131
10

What is the solution to the equation ?

Question illustration
A
x =
Option A
B
x =
Option B
C
x = 3
D
x = 7

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Lesson 1.1: Solving Equations Answers…