AnswersOC27 MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006PLiteral Equations

Lesson 1.3: Literal Equations Answers

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The formula for the area of a regular polygon is . What is the equation solved for a?

Question illustration
A
a = 2 uppercase A
Option A
B
a = 2 uppercase A minus p
Option B
C
a = StartFraction 2 p Over uppercase A EndFraction
Option C
D
a = StartFraction 2 uppercase A Over p EndFraction
Option D
2
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The formula for the nth term of an arithmetic sequence can be found using the formula . Which of the following is equivalent to this equation?

Question illustration
A
n = a Subscript n Baseline + a Subscript 1
Option A
B
n = StartFraction a Subscript n Baseline + a Subscript 1 Baseline minus 3 Over d EndFraction
Option B
C
n = a Subscript n Baseline minus a Subscript 1
Option C
D
n = a Subscript n Baseline minus a Subscript 1 Baseline + d Over d EndFraction
Option D
3

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

Question illustration
A
uppercase V squared minus v squared minus 2 x = a
Option A
B
uppercase V squared minus v squared + 2 s = a
Option B
C
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Option C
D
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Option D
4

The formula gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Question illustration
A
a Subscript n Baseline = StartFraction 2 uppercase S minus a Subscript 1 Baseline n Over n EndFraction
Option A
B
a Subscript n Baseline = StartFraction 2 uppercase S + a Subscript 1 Baseline n Over n EndFraction
Option B
C
a Subscript n Baseline = 2 uppercase S + a Subscript 1 Baseline n + n
Option C
D
a Subscript n Baseline = 2 uppercase S minus a Subscript 1 Baseline n + n
Option D
5

The equation is the slope-intercept form of the equation of a line. What is the equation solved for b?

Question illustration
A
y minus m = b
Option A
B
y minus m x = b
Option B
C
StartFraction y Over m x EndFraction = b
Option C
D
StartFraction y Over m EndFraction minus x = b
Option D
6

Remmi wrote the equation of the line He solved for x and got Which of the following is an equivalent equation for x?

Question illustration
A
x = y minus eleven-thirds
Option A
B
x = y + seven-thirds
Option B
C
x = 3 (y minus two-thirds)
Option C
D
x = 3 (y + two-thirds)
Option D
7

If , which equation is solved for t?

Question illustration
A
I – pr = t
B
StartFraction uppercase I minus p Over r EndFraction = t
Option B
C
StartFraction uppercase I Over p r EndFraction = t
Option C
D
I + pr = t
8

Given the equation , which equation is solved for t?

Question illustration
A
t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)
Option A
B
t = p minus s Subscript 1 Baseline minus s Subscript 2
Option B
C
t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
Option C
D
t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction
Option D
9

Paolo wrote the following equation for the perimeter of a rectangle. Which equation is equivalent to the equation Paolo wrote?

Question illustration
A
w = uppercase P minus 2 l
Option A
B
2 = uppercase P minus l
Option B
C
w = StartFraction uppercase P minus 2 l Over 2 EndFraction
Option C
D
w = StartFraction uppercase P + 2 l Over 2 EndFraction
Option D
10

Which equation is equivalent to

Question illustration
A
s = t minus 2
Option A
B
s = StartFraction 4 Over t + 2 EndFraction
Option B
C
s = StartFraction t + 2 Over 4 EndFraction
Option C
D
s = t + 6
Option D

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