Lesson 1.7: Solving Absolute Value Equations Answers

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3

What value or values of x satisfy 2|x + 5.3| = 4.2?

A
x can only equal –3.2.
B
x can only equal 7.4.
C
x can equal –3.2 or –7.4.
D
x can equal –3.2 or 7.4.
4

Which statements are true? Check all that apply.The equation |–x – 4| = 8 will have two solutions.The equation 3.4|0.5x – 42.1| = –20.6 will have one solution.The equation [image 1] = 0 will have no solutions.The equation |2x – 10| = –20 will have two solutions.The equation |0.5x – 0.75| + 4.6 = 0.25 will have no solutions.The equation [image 2] = 5 will have infinitely many solutions.

Question illustration
A
The equation |–x – 4| = 8 will have two solutions.
B
The equation 3.4|0.5x – 42.1| = –20.6 will have one solution.
C
The equation = 0 will have no solutions.
Option C
D
The equation |2x – 10| = –20 will have two solutions.
E
The equation |0.5x – 0.75| + 4.6 = 0.25 will have no solutions.
F
The equation = 5 will have infinitely many solutions.
Option F
6

Which statements are true for solving the equation 0.5 – |x – 12| = –0.25? Check all that apply.The equation will have no solutions.A good first step for solving the equation is to subtract 0.5 from both sides of the equation.A good first step for solving the equation is to split it into a positive case and a negative case.The positive case of this equation is 0.5 – |x – 12| = 0.25.The negative case of this equation is x – 12 = –0.75.The equation will have only 1 solution

A
The equation will have no solutions.
B
A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
C
A good first step for solving the equation is to split it into a positive case and a negative case.
D
The positive case of this equation is 0.5 – |x – 12| = 0.25.
E
The negative case of this equation is x – 12 = –0.75.
F
The equation will have only 1 solution
7

What did you include in your response? Check all that apply.

A
Absolute values cannot be equal to negative values.
B
There were no viable solutions.
C
Absolute values represent distances from values, which cannot be negative.
14

Max’s starting distance from KimThe time it takes Max to reach Kim✔ Max’s constant speed

A
Max’s starting distance from Kim
B
The time it takes Max to reach Kim
C
✔ Max’s constant speed

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