A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. If it takes 0.070 N of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle?

The force keeping the beetle moving in a circle is the centripetal force, given by F = mv²/r. Rearranging gives v = √(Fr/m) = √[(0.070 N)(0.15 m)/(0.023 kg)] ≈ 0.68 m/s. Therefore, the tangential speed is 0.68 m/s, choice A.

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