A 115 point 0 - g sample of oxygen was produced by heating 400 point 0 g of potassium chlorate. 2 KClO sub 3 rightarrow 2 KCl plus 3 cap o sub 2 What is the percent yield of oxygen in this chemical reaction? Use percent Yield is equal to Actual yield over Theoretical yield times 100

The balanced equation shows that 2 mol of KClO₃ produce 3 mol of O₂. Using molar masses, 400.0 g KClO₃ produces a theoretical yield of about (400.0 ÷ 122.55) × (3 ÷ 2) × 32.00 = 156.7 g O₂. The percent yield is (115.0 ÷ 156.7) × 100 ≈ 73.40%, so the correct choice is 73.40 percent.

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