Salicylic acid open paren cap c sub 7 cap h sub 6 cap o sub 3 close paren reacts with acetic anhydride open paren cap c sub 4 cap h sub 6 cap o sub 3 close paren to form acetylsalicylic acid open paren cap c sub 9 cap h sub 8 cap o sub 4 close paren 2 cap c sub 7 cap h sub 6 cap o sub 3 aq plus cap c sub 4 cap h sub 6 cap o sub 3 aq rightarrow 2 cap c sub 9 cap h sub 8 cap o sub 4 aq plus cap h sub 2 cap o l What is the limiting reactant if 70 point 0 g of open paren cap c sub 7 cap h sub 6 cap o sub 3 close paren and 80 point 0 g of open paren cap c sub 4 cap h sub 6 cap o sub 3 close paren react?
The balanced equation uses 2 mol of salicylic acid for every 1 mol of acetic anhydride. The amounts given are 70.0 g ÷ 138.12 g/mol ≈ 0.507 mol salicylic acid and 80.0 g ÷ 102.09 g/mol ≈ 0.784 mol acetic anhydride. The salicylic acid would need only about 0.254 mol acetic anhydride, so acetic anhydride is in excess and salicylic acid is the limiting reactant.
AI-written and checked against the verified answer.