Question 4 • Precalculus
This is a geometric series with first term 1/8 and common ratio 1/2. Its first n terms sum to (1/8)(1 − (1/2)^n)/(1 − 1/2) = (2^n − 1)/(4·2^n). Taking the limit as n approaches infinity gives choice A, which defines the sum of the series.
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