Question 17 • *KCPS Algebra I (2027)
The equation is in point-slope form: y − 1 = (2/3)(x − 3), so the line passes through (3, 1) and has slope 2/3. Moving 6 units left from x = 3 changes y by (2/3)(−6) = −4, giving the point (−3, −3). Choice D shows a line through (−3, −3) and (3, 1).
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