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Literal Equations Answers

11 verified answers
1
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Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

A
– r = h
Option A
B
= h
Option B
C
S – = h
Option C
D
S – = h
Option D
2
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Which are equivalent equations? Select two correct answers.

A
s =
Option A
B
s =
Option B
C
s = LAr
Option C
D
r =
Option D
E
r = LAs
Option E
3

Solve the equation for a.K = 4a + 9ab

Question illustration
a
a = K(4 + 9b)
a
a = 4(K + 9b)
a
a =
Option a
a
a =
Option a
4

The formula for the circumference of a circle is C = 2r, where r is the radius and C is the circumference. The equation solved for r is r = .

Question illustration
r
r = 4
r
r = 8
r
r = 12
r
r = 16
5

The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equation solved for V?

Question illustration
d
dm = V
=
= V
Option =
=
= V
Option =
m
m – d = V
6

The goals against average (A) for a professional hockey goalie is determined using the formula A = 60 . In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes.

Question illustration
A
= g
Option A
B
= g
Option B
C
= g
Option C
D
60At = g
7

Solve for a.7a - 2b = 5a + b

A
a = 2b
B
a = 3b
C
a = b
Option C
D
a = b
Option D
8

Solve for w.5w + 9z = 2z + 3w

Question illustration
w
w = z
Option w
w
w = z
Option w
w
w = –2z
w
w = –7z
9

The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the equation K = C + 273.15.

C
C = K – 273.15
C
C = 273.15 – K
C
C = K + 273.15
C
C = 273.15K
10

The slope, m, of a linear equation can be found using the formula m = , where the x- and y-values come from two ordered pairs, and (x1, y1) and (x2, y2).

Question illustration
A
y2 = mx2 – x1 + y1
B
y2 = mx2 – x1 – y1
C
y2 = m(x2 – x1) + y1
D
y2 = m(x2 – x1) – y1
11

The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equation solved for V?

Question illustration
A
dm = V
B
= V
Option B
C
= V
Option C
D
m – d = V
12

The equation f = v + at represents the final velocity of an object, f, with an initial velocity, v, and an acceleration rate, a, over time, t.

A
t =
Option A
B
t =
Option B
C
t = a(f – v)
D
t = v(f – a)
13

The goals against average (A) for a professional hockey goalie is determined using the formula A = 60 . In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes.

Question illustration
A
= g
Option A
B
= g
Option B
C
= g
Option C
D
60At = g
14

The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the equation K = C + 273.15.

A
C = K – 273.15
B
C = 273.15 – K
C
C = K + 273.15
D
C = 273.15K
15

In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the equation F=ma.Using this formula, what is the acceleration of an object with F=7.92 newtons and m=3.6 kilograms? Express your answer to the nearest tenth.Note: The unit for Force (the Newton) is measured in .

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
16

The formula for the circumference of a circle is C = 2r, where r is the radius and C is the circumference. The equation solved for r is r = .

Question illustration
A
r = 4
B
r = 8
C
r = 12
D
r = 16
17

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

A
– r = h
Option A
B
= h
Option B
C
S – = h
Option C
D
S – = h
Option D
18

Solve the equation for a.K = 4a + 9ab

A
a = K(4 + 9b)
B
a = 4(K + 9b)
C
a =
Option C
D
a =
Option D
19

The circumference of a circle can be found using the formula C = 2r.

Question illustration
A
r = C
Option A
B
r = C(2)
Option B
C
r =
Option C
D
r =
Option D
20

The slope, m, of a linear equation can be found using the formula m = , where the x- and y-values come from two ordered pairs, and (x1, y1) and (x2, y2).

Question illustration
A
y2 = mx2 – x1 + y1
B
y2 = mx2 – x1 – y1
C
y2 = m(x2 – x1) + y1
D
y2 = m(x2 – x1) – y1

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