AnswersOC27 MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006PLiteral Equations

Literal Equations Answers

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The formula gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Question illustration
A
a Subscript n Baseline = StartFraction 2 uppercase S minus a Subscript 1 Baseline n Over n EndFraction
Option A
B
a Subscript n Baseline = StartFraction 2 uppercase S + a Subscript 1 Baseline n Over n EndFraction
Option B
C
a Subscript n Baseline = 2 uppercase S + a Subscript 1 Baseline n + n
Option C
D
a Subscript n Baseline = 2 uppercase S minus a Subscript 1 Baseline n + n
Option D
2
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The formula for the area of a regular polygon is . What is the equation solved for a?

Question illustration
A
a = 2 uppercase A
Option A
B
a = 2 uppercase A minus p
Option B
C
a = StartFraction 2 p Over uppercase A EndFraction
Option C
D
a = StartFraction 2 uppercase A Over p EndFraction
Option D
3

If , which equation is solved for t?

Question illustration
A
I – pr = t
B
StartFraction uppercase I minus p Over r EndFraction = t
Option B
C
StartFraction uppercase I Over p r EndFraction = t
Option C
D
I + pr = t
4

When is solved for c, one equation is Which of the following is an equivalent equation to find c?

Question illustration
A
c = 10 b minus 10 minus 5
Option A
B
c = (10 b minus 10 minus 5) squared
Option B
C
c = StartFraction (10 b minus 2) squared Over 25 EndFraction
Option C
D
c = StartFraction (10b minus 10) squared Over 25 EndFraction
Option D
5

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solved for m?

A
m = StartFraction s minus c Over c EndFraction
Option A
B
m = StartFraction s + c Over c EndFraction
Option B
C
s minus c = m
Option C
D
s + c = m
Option D
6

Remmi wrote the equation of the line He solved for x and got Which of the following is an equivalent equation for x?

Question illustration
A
x = y minus eleven-thirds
Option A
B
x = y + seven-thirds
Option B
C
x = 3 (y minus two-thirds)
Option C
D
x = 3 (y + two-thirds)
Option D
7

A student solves the equation using the steps in the table. Original equationCross multiplicationDistributive propertySubtraction property of equality5 = xWhich method of solving for the variable could be used instead of cross multiplication?

Question illustration
A
distributing x + 3 and then 3x + 5 to both sides of the equation
B
distributing x – 3 and then 3x – 5 to both sides of the equation
C
using the multiplication property of equality to multiply both sides of the equation by 10
D
using the multiplication property of equality to multiply both sides of the equation by
Option D
8

The formula for the nth term of an arithmetic sequence can be found using the formula . Which of the following is equivalent to this equation?

Question illustration
A
n = a Subscript n Baseline + a Subscript 1
Option A
B
n = StartFraction a Subscript n Baseline + a Subscript 1 Baseline minus 3 Over d EndFraction
Option B
C
n = a Subscript n Baseline minus a Subscript 1
Option C
D
n = a Subscript n Baseline minus a Subscript 1 Baseline + d Over d EndFraction
Option D
9

The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

Question illustration
A
360 uppercase A + pi r squared
Option A
B
360 uppercase A minus pi r squared
Option B
C
StartFraction 360 + uppercase A Over pi r squared EndFraction
Option C
D
StartFraction 360 uppercase A Over pi r squared EndFraction
Option D
10

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

Question illustration
A
uppercase V squared minus v squared minus 2 x = a
Option A
B
uppercase V squared minus v squared + 2 s = a
Option B
C
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Option C
D
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Option D
11

Gavin wrote the equation to represent p, the profit he makes from s sales in his lawn-mowing business. Which equation is solved for s?

Question illustration
A
s = StartFraction p minus 100 Over 3 EndFraction
Option A
B
s = StartFraction 4 p minus 300 Over 3 EndFraction
Option B
C
s = StartFraction 4 p Over 300 EndFraction
Option C
D
s = StartFraction 400 p Over 3 EndFraction
Option D
12

The equation is the slope-intercept form of the equation of a line. What is the equation solved for b?

Question illustration
A
y minus m = b
Option A
B
y minus m x = b
Option B
C
StartFraction y Over m x EndFraction = b
Option C
D
StartFraction y Over m EndFraction minus x = b
Option D
13

Which of the following equations is equivalent to ?

Question illustration
A
h = uppercase S minus pi r squared
Option A
B
h = StartFraction uppercase S Over pi r squared EndFraction
Option B
C
h = StartFraction pi r squared Over uppercase S EndFraction
Option C
D
h = uppercase S + pi r squared
Option D
14

Which equation is equivalent to

Question illustration
A
s = t minus 2
Option A
B
s = StartFraction 4 Over t + 2 EndFraction
Option B
C
s = StartFraction t + 2 Over 4 EndFraction
Option C
D
s = t + 6
Option D
15

Given the equation , which equation is solved for t?

Question illustration
A
t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)
Option A
B
t = p minus s Subscript 1 Baseline minus s Subscript 2
Option B
C
t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
Option C
D
t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction
Option D
16

Cary calculated the surface area of a box in the shape of a rectangular prism. She wrote the equation to represent the width and height of the box. She solved for w and got Which of the following is an equivalent equation?

Question illustration
A
w = StartFraction 148 minus 6 h Over 12 + h EndFraction
Option A
B
w = StartFraction 148 minus 12 h Over 12 + 2 h EndFraction
Option B
C
w = 136 minus 14 h
Option C
D
w = 136 minus 10 h
Option D
17

Paolo wrote the following equation for the perimeter of a rectangle. Which equation is equivalent to the equation Paolo wrote?

Question illustration
A
w = uppercase P minus 2 l
Option A
B
2 = uppercase P minus l
Option B
C
w = StartFraction uppercase P minus 2 l Over 2 EndFraction
Option C
D
w = StartFraction uppercase P + 2 l Over 2 EndFraction
Option D
18

A student solves the equation for v. Start with the original equation.Use the division property of equality.Use the multiplication property of equality.Use the square root property of equality.Simplify.Which statement explains how to correct the error that was made?

Question illustration
A
The subtraction property of equality should have been applied to move m to the other side of the equation.
B
The multiplication property of equality should have been applied in the last step.
C
The division property of equality should have been used to divide by k instead of m.
D
The square root property should have been applied to both complete sides of the equation instead of to select variables.

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