What is the force exerted on a charge of 2.5 µC moving perpendicular through a magnetic field of 3.0 × 102 T with a velocity of 5.0 × 103 m/s?

For a charge moving perpendicular to a magnetic field, the force is F = qvB. Substituting the values gives F = (2.5 × 10⁻⁶ C)(5.0 × 10³ m/s)(3.0 × 10² T) = 3.75 N, which rounds to 3.8 N. Therefore, the correct choice is A, 3.8 N.

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