A point charge of 6 point 8 mu cap c moves at 6 point 5 times 10 to the 4th power m/s at an angle of 15 degrees to a magnetic field that has a field strength of 1 point 4 cap t What is the magnitude of the magnetic force acting on the charge?

Use the magnetic-force formula F = qvB sin θ. Substituting q = 6.8 × 10⁻⁶ C, v = 6.5 × 10⁴ m/s, B = 1.4 T, and θ = 15° gives F ≈ (6.8 × 10⁻⁶)(6.5 × 10⁴)(1.4)sin(15°) ≈ 0.16 N = 1.6 × 10⁻¹ N. This matches choice C, 1.6 × 10⁻¹ N.

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