How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? Set 1: 12, 8, 10, 50Set 2: 13, 9, 8

Set 1 has a mean of (12 + 8 + 10 + 50) ÷ 4 = 20, and its absolute deviations average (8 + 12 + 10 + 30) ÷ 4 = 15. Set 2 has a mean of 10, and its absolute deviations average (3 + 1 + 2) ÷ 3 = 2. Since 15 − 2 = 13, the MAD of set 1 is 13 more than the MAD of set 2, choice B.

AI-written and checked against the verified answer.