How does the mean absolute deviation (MAD) of the data in set 2 compare to the mean absolute deviation of the data in set 1? Set 1: 16, 15, 10, 12Set 2: 16, 62, 15, 10, 12

Set 1 has a mean of 13.25, and its absolute deviations average to (2.75 + 1.75 + 3.25 + 1.25) ÷ 4 = 2.25. Set 2 has a mean of 23, and its absolute deviations average to (7 + 39 + 8 + 13 + 11) ÷ 5 = 15.6. The difference is 15.6 − 2.25 = 13.35, so the MAD of set 2 is 13.35 more than the MAD of set 1.

AI-written and checked against the verified answer.