How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2?Set 1: 5, 10, 7, 2Set 2: 5, 10, 7, 42

Set 1 has a mean of (5 + 10 + 7 + 2) ÷ 4 = 6, and its absolute deviations from 6 average (1 + 4 + 1 + 4) ÷ 4 = 2.5. Set 2 has a mean of (5 + 10 + 7 + 42) ÷ 4 = 16, and its absolute deviations average (11 + 6 + 9 + 26) ÷ 4 = 13. Since 2.5 is 10.5 less than 13, the MAD of set 1 is 10.5 less than the MAD of set 2.

AI-written and checked against the verified answer.