Question 6 • Chemistry
There are 10 beakers, each holding 250 mL, so the total solution volume is 2.50 L. At 0.720 mol/L, that requires 0.720 × 2.50 = 1.80 mol of CaCl₂. Multiplying by its molar mass gives 1.80 mol × 110.98 g/mol = 199.8 g, which rounds to 200 g.
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