A 15.0 cm object is 12.0 cm from a concave mirror that has a focal length of 4.8 cm. Its image is 8.0 cm in front of the mirror.What is the approximate height of the image produced by the mirror?

For a mirror, magnification is the negative of image distance divided by object distance: m = −8.0/12.0 = −2/3. The image height is hᵢ = m hₒ = (−2/3)(15.0 cm) = −10 cm. The negative sign means the image is inverted, so the answer is −10 cm.

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