AnswersFL-1200330-Algebra 2 CRModeling with Exponential and Logarithmic Equations

Modeling with Exponential and Logarithmic Equations Answers

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1
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The loudness of a jack hammer is 96 dB. Its sound intensity is about 0.0096 0.0040.0021.

A
0.0096
B
0.004
C
0.0021
2
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The loudness of a compactor is 94 dB. Its sound intensity is about 0.00250.00430.0081.

A
0.0025
B
0.0043
C
0.0081
3

The sound intensity of the jack hammer is about 2.051.851.6 times the sound intensity of the compactor.

A
2.05
B
1.85
C
1.6
4

The loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a pile driver? Round to the nearest ten.

Answer:

40

5

a = ⇒ -76.204 b =

Answer:

0.814

6

Question text not available

Answers:
Blank 1:-76.204
Blank 2:37.673
7

Using the graphing calculator, estimate to the nearest day how long it will take the corn to reach 6 feet tall: days

A
45
B
51
C
63
D
72
8

How would you explain the relationship between the real zero(s) of the function and x-intercept(s) of the graph?

A
Since the graph crosses the x-axis at x = – 2, the function has a real zero of x = – 2.
B
Since the graph never crosses the x-axis, the function has no real zeros.
C
Since the graph eventually crosses the x-axis, the function has a real zero.
D
Since the graph crosses the y-axis at , the function results in a real zero of x = ?.
9

Which equation has real zeros corresponding to the x-intercepts of the graph?

A
y = log3(x) – 1
B
y = 3x – 3
C
y = –3(x – 1) + 3
D
y = log3(2x) – 2
10

Which equation can you use to solve this problem?

A
Option
B
Option
C
Option
11

After 100 years, about 60100115 grams of the sample will remain.

A
60
B
100
C
115
12

The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. What is the approximate pH of a solution if the concentration of hydrogen ions is 5.0 × 10–4 moles per liter?

A
2.7
B
3.0
C
3.3
D
3.6
13

The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $

Answer:

12528.15

14

After 10 years, a $2,000-dollar investment compounded annually has grown to $3600. What is the interest rate to the nearest whole-number percent? %

Answer:

6%

15

b =

Answer:

37.673

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