AnswersFL-1200330-Algebra 2 CRSolving Exponential and Logarithmic Equations

Modeling with Exponential and Logarithmic Equations Answers

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1
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Predict: Imagine a small pond with just 4 water lilies. Guess how many lilies will be in the pond just a month later:

Answer:

Answer

2
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1 day: ⇒ 4

Answer:

4

3

2 days: ⇒ 5

Answer:

5

4

3 days: ⇒ 6

Answer:

6

5

4 days: ⇒ 6

Answer:

6

6

5 days: ⇒ 7

Answer:

7

7

Drag the slider to see the number of water lilies in the pond each day. Collect the data and fill in the text boxes below.

Answers:
0 days::4
1 day::4
2 days::5
3 days::6
4 days::6
5 days::7
8

Your prediction on the previous page was .

A
way too low
B
too low
C
about right
D
too high
E
way too high
9

The data show that the population of lily pads has a steady ✔ an increasing a decreasing growth rate.

Answer not available
10

A logarithmic✔ An exponentialA linearA quadratic function would be most suitable to model these data.

Answer not available
11

The general form of an exponential function is y = abx. Use the regression calculator to find the values of a and b for the water lily population growth. Round to the nearest thousandth. a = ⇒ 3.915 and b =

Answers:
⇒ 3.915:15.111 and 1.488
Blank 2:1.106
12

The graph to the right shows what you should have gotten on the regression calculator. Check all statements below that accurately describe the regression equation.

A
Some points do not lie on the regression curve, so it is not a good model.
B
Most points lie on or near the regression curve, so it is a good model.
C
The equation can be used to analyze the population growth, and to estimate values outside of what was collected.
13

In terms of the water lily population change, the value 3.915 represents:

Answer:

The value of 3.915 is the initial number of water lilies. It is approximately 4, which matches the data. The value 1.106 is the growth rate. The rate represents growth for each day. The percentage growth each day is 10.6%

14

Which of the following did you include in your description?

A
The value of 3.915 is the initial number of water lilies.
B
It is approximately 4, which matches the data.
C
The value 1.106 is the growth rate.
D
The rate represents growth for each day.
E
The percentage growth each day is 10.6%
15

Which two equations below could you solve to find D, the number of days it takes the water lily population to double?

A
2 = 3.915(1.106)D
B
7.830 = 3.915(1.106)D
C
7.830 = 3.915(2)D
D
2 = 1.106D
16

Solve either of the correct equations using any method. Round to the nearest whole number.D = days

Answer:

7

17

Day 0: plants Day 7: plants Did the water lilies double? Day 10: plants Day 17: plants Did the water lilies double?

Answers:
Selection 1:Yes
Selection 2:Approximately
18

The slider only goes up to day 30, but this pond can hold up to 400 water lilies. Estimate the day that the pond will be full. Day

Answer:

32

19

Which solution method did you use?

A
Logarithms
B
Graphing y = 3.915(1.106)x and tracing
C
Graphing y = 3.915(1.106)x and y = 400, then finding the x-value of the intersection
20

The pond can hold 400 water lilies. By what day will the pond be full? Write and solve an equation.The pond will be full by the end of day .

Answer:

46

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