A projectile is launched straight up from the ground with an initial velocity of 120 ft/s. If acceleration due to gravity is –16 ft/s2, after about how many seconds will the object reach a height of 200 ft?h(t) = at2 + vt + h0

Use the height formula with acceleration −16 ft/s², initial velocity 120 ft/s, and starting height 0: h(t) = −16t² + 120t. Set the height to 200: −16t² + 120t = 200, which gives 2t² − 15t + 25 = 0. The solutions are 2.5 and 5 seconds; the object first reaches 200 ft after 2.5 seconds, choice C.

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