Question 8 • FL-1200330-Algebra 2 CR
Let x be the increase in both the length and width. The new area is (120 + x)(80 + x), so the increase is x² + 200x; set this equal to 4,400. Solving x² + 200x − 4,400 = 0 gives the positive solution x = 20, so the length should be increased by 20 ft (choice B).
AI-written and checked against the verified answer.