AnswersFL-1200330-Algebra 2 CRModeling with Quadratic Equations

Modeling with Quadratic Equations Answers

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A projectile is launched straight up from the ground with an initial velocity of 120 ft/s. If acceleration due to gravity is –16 ft/s2, after about how many seconds will the object reach a height of 200 ft?h(t) = at2 + vt + h0

A
1.0 s
B
1.7 s
C
2.5 s
D
8.0 s
2
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The Davidson family wants to expand its rectangular patio, which currently measures 15 ft by 12 ft. They want to extend the length and width the same amount to increase the total area of the patio by 160 ft2. Which quadratic equation best models the situation?A = lw

A
(15)(12) + (x)(x) = (15)(12) + 160
B
(15x)(12x) = (15)(12) + 160
C
2(15 + x) + 2(12 + x) = (15)(12) + 160
D
(15 + x)(12 + x) = (15)(12) + 160
3

A box is to be constructed with a rectangular base and a height of h cm. The length, l, of the box is 10 cm, and the width, w, is twice the height. Which quadratic equation best models the volume of the box? V = lwh

A
V = 20h
B
V = 20h2
C
V = 100h
D
V = 100h2
4

A softball pitcher tosses a ball straight upward from a height of 3 feet above the ground with an initial velocity of 50 feet per second. The acceleration due to gravity is –16 ft/s².Which quadratic equation represents the height of the ball above the ground after t seconds?h(t) = at2 + vt + h0

A
h(t) = 50t2 – 16t + 3
B
h(t) = –16t2 + 50t + 3
C
3 = –16t2 + 50t + h0
D
3 = 50t2 – 16t + h0
5

The total area of two square windows is 1,025 in.2. Each side of the larger window is 5 in. longer than the sides of the smaller window. How long are the sides of the smaller window?A = s2

A
13.5 in.
B
20 in.
C
25 in.
D
31.6 in.
6

A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t2 + 40t + 7. Rounded to the nearest tenth, the solutions to the equation when h(t) = 0 feet are –0.2 s and 2.7 s. Which solution can be eliminated and why?

A
The solution –0.2 s can be eliminated because time cannot be a negative value.
B
The solution –0.2 s can be eliminated because the pass was not thrown backward.
C
The solution 2.7 s can be eliminated because the pass was thrown backward.
D
The solution 2.7 s can be eliminated because a ball cannot be in the air for that long due to gravity.
7

A car’s stopping distance in feet is modeled by the equation where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?

Question illustration
A
21 feet
B
21 miles
C
239 feet
D
239 miles
8

Two children are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s. If acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?h(t) = at2 + vt + h0

A
12 ft
B
20 ft
C
76 ft
D
116 ft
9

A rectangular pan has a length that is the width. The total area of the pan is 432 in.2. What is the width of the cake pan?A = lw

Question illustration
Answer not available
10

Justin and Elena each launched a toy rocket into the air. The height of Justin’s rocket is modeled by the equation h = –16t2 + 60t + 2. Elena launched his rocket from the same position, but with an initial velocity double that of Justin’s. Which equation best models the height of Elena’s rocket?h(t) = at2 + vt + h0

A
h = –16t2 + 60t + 4
B
h = –32t2 + 120t + 4
C
h = –32t2 + 60t + 2
D
h = –16t2 + 120t + 2
11

A skydiver jumps from an airplane at an altitude of 2,500 ft. He falls under the force of gravity until he opens his parachute at an altitude of 1,000 ft. Using the initial velocity of zero, approximately how long does the jumper fall before he opens his chute?For this quadratic model we will let the y-axis be the axis of symmetry.h(t) = -16t2 + vt + h0

A
2.4 s
B
9.7 s
C
12.5 s
D
14.8 s
12

A baseball is thrown into the air from a height of 5 feet. The ball reaches a maximum height of 43.5 feet and spends a total of 3.2 seconds in the air. Which equation models the height of the baseball? Assume that acceleration due to gravity is –16 ft/s2.

A
h(t) = 16t2 + 49.64t + 5
B
h(t) = -16t2 + 5t + 49.64
C
h(t) = -16t2 + 49.64t + 5
D
h(t) = 16t2 + 5t + 49.64
13

A firework is launched into the air from ground level with an initial velocity of 128 ft/s. If acceleration due to gravity is –16 ft/s2, what is the maximum height reached by the firework?h(t) = at2 + vt + h0

A
256 ft
B
448 ft
C
512 ft
D
1,024 ft
14

When using a quadratic equation in the form y = ax2 + bx + c to model the height of a projectile (y) over time (x), which of the following is always represented by the constant term?

A
the initial height of the projectile
B
the initial velocity of the projectile
C
the time at which the projectile hits the ground
D
the maximum height of the projectile
15

Both Rachel and Dominique throw tennis balls into the air. At any time, t, the height, h, of Rachel’s ball is modeled by the equation h = –16t2 + 30t + 5. Dominique throws his tennis ball with the same acceleration, a, from the same initial height, , but with an initial velocity, v, double that of Rachel’s. Which equation best models the height of Dominique’s tennis ball?h(t) = at2 + vt + h0

Question illustration
A
h = –16t2 + 30t + 10
B
h = –32t2 + 60t + 10
C
h = –32t2 + 30t + 5
D
h = –16t2 + 60t + 5
16

A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s in the air, which equation models the height of the ball correctly? Assume that acceleration due to gravity is –16 ft/s2.h(t) = at2 + vt + h0

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
17

Carmen is using the quadratic equation (x + 15)(x) = 100 where x represents the width of a picture frame. Which statement about the solutions x = 5 and x = –20 is true?

A
The solutions x = 5 and x = –20 are reasonable.
B
The solution x = 5 should be kept, but x = –20 is unreasonable.
C
The solution x = –20 should be kept, but x = 5 is unreasonable.
D
The solutions x = 5 and x = –20 are unreasonable.

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