Which statement describes the vertical asymptotes of the graph of f of x is equal to the fraction with numerator x squared minus 64 and denominator 8 x minus 64 ?

Factor the numerator and denominator: x² − 64 = (x − 8)(x + 8), and 8x − 64 = 8(x − 8). For x ≠ 8, the common factor cancels, leaving (x + 8)/8, so x = 8 is a removable hole rather than a vertical asymptote. There is no remaining denominator that can become zero, so the graph has no vertical asymptote: choice A.

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