Given f of x is equal to 3 and g x is equal to cosine of x What is the limit? limit x to negative pi of open bracket f of x minus g of x close bracket

Since f(x) = 3 and g(x) = cos(x), the expression is 3 − cos(x). Cosine is continuous, so evaluate at x = −π: cos(−π) = −1, giving 3 − (−1) = 4. The limit is 4, choice A.

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