Question 16 • Precalculus
Factor the numerator using the difference of cubes: x³ − 1 = (x − 1)(x² + x + 1). For x ≠ 1, cancel the common factor x − 1, then substitute x = 1 to get 1² + 1 + 1 = 3. The limit is 3, so the correct choice is B.
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