Question 1 • (OC27) MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006P
Let c be the commission for a car and t the commission for a truck. The sales totals give 6c + 3t = 4,800 and 8c + t = 4,600; simplifying the first gives 2c + t = 1,600, so subtracting it from the second gives 6c = 3,000 and c = $500. Then t = $600, so 2 cars and 3 trucks earn 2($500) + 3($600) = $2,800, choice C.
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