Question 2 • FL-1200700-Mathematics for College Algebra MIS
Let n be the number of nickels and d the number of dimes. The coin count gives n + d = 44, and the value in nickel units gives n + 2d = 62 because $3.10 is 62 nickels. Subtracting the first equation from the second gives d = 18, so n = 26. The nickels are worth 26 × $0.05 = $1.30, which is choice B.
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