Question 16 • Precalculus
Shifting sine 3π/2 units left gives y = sin(x + 3π/2), and shifting it 11 units down gives y = sin(x + 3π/2) − 11. At x = 0, the value is sin(3π/2) − 11 = −12, the minimum of the function. Its maximum is −10 and its period is 2π, matching the graph that meets the y-axis at (0, −12).
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