How does the graph of y is equal to secant of open paren x plus 3 close paren minus 7 compare with the graph of y is equal to secant of x ?

In y = sec(x + 3) − 7, adding 3 inside the input shifts the graph 3 units left. Subtracting 7 outside the function shifts it 7 units down. Therefore, the graph is shifted 3 units left and 7 units down.

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