Question 4 • LA-Chemistry A
BF₃ contains one boron atom and three fluorine atoms. Using atomic masses of about 10.81 g/mol for boron and 19.00 g/mol for fluorine, its molar mass is 10.81 + 3(19.00) = 67.81 g/mol. Therefore, the correct choice is 67.81 g/mol.
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