Question 12 • 2025-2026 FBISD - Precalculus A (CR)
A cube’s side length s cannot be negative, so s ≥ 0. Its volume V = s³ is also nonnegative, placing the graph in quadrant I (and at the origin when s = 0). Quadrant III would require a negative side length and a negative volume, which are not physically possible.
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